基于EDA技术如何实现抢答和显示器的设计？

graph TB
    subgraph 抢答系统
    A[按键输入模块] -->|防抖处理| B[抢答裁决模块]
    B -->|选手编号| C[显示驱动模块]
    C --> D[数码管/LED显示]
    E[主持人控制] -->|复位/开始| B
    F[时钟分频模块] --> B & C
    end

-- VHDL 按键消抖示例
entity debounce is
    Port ( clk : in STD_LOGIC;
           button_in : in STD_LOGIC;
           button_out : out STD_LOGIC);
end debounce;

architecture Behavioral of debounce is
    signal count : integer range 0 to 100000 := 0; -- 10ms计数器（假设50MHz时钟）
begin
    process(clk)
    begin
        if rising_edge(clk) then
            if button_in /= button_out then
                count <= count + 1;
                if count = 100000 then 
                    button_out <= button_in;
                end if;
            else
                count <= 0;
            end if;
        end if;
    end process;
end Behavioral;

// Verilog 抢答裁决逻辑
module arbiter(
    input clk,
    input reset,
    input start,
    input [7:0] buttons,
    output reg [3:0] winner // 4bit编码支持16路
);

reg [1:0] state;
parameter IDLE=0, LISTEN=1, LOCK=2;

always @(posedge clk or posedge reset) begin
    if (reset) begin
        state <= IDLE;
        winner <= 4'b0;
    end else case(state)
        IDLE: if (start) state <= LISTEN;
        LISTEN: 
            if (buttons != 8'b1111_1111) begin // 有按键按下
                winner <= priority_encoder(buttons); // 优先级编码器
                state <= LOCK;
            end
        LOCK: ; // 保持锁定状态直到复位
    endcase
end

// 优先级编码器函数（检测最低位0）
function [3:0] priority_encoder;
    input [7:0] btn;
    begin
        casez(btn) // 综合工具自动生成优先级逻辑
            8'b???????0: priority_encoder = 1;
            8'b??????01: priority_encoder = 2;
            ... // 依此类推
        endcase
    end
endfunction
endmodule

// 10秒倒计时计数器
always @(posedge clk or posedge reset) begin
    if (reset) time_left <= 10;
    else if (state == LISTEN) begin
        if (clk_1Hz) time_left <= time_left - 1; // 1Hz时钟分频
        if (time_left == 0) state <= LOCK;        // 超时处理
    end
end

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